10-17-08

**10/17/08** ** Homework, ** ** VT Graph Due Monday, was given out on Friday(10/17) ** Today we started class by going over the Driving Mr. Physics Packet. In case you were wondering what the answers were, we started at pg 24 question #6. The correct answer for question 6 was acceleration was equal to 2.92m/s. The answer for #7 was 12m/s. To get number question 7 on pg 25, you must first start out with the equation, velocity =acceleration multiplied by time. Number 8’s answer was zero. For question 9 on page 25, you had to draw lines on the VT graph that corresponded to the directions given. For question 9 the graph on the left started at a positive position and moved in a downwards direction. On graph on the right for question 9, the line started at a negative position and moved in an upwards position. The answers to the Daily Question were, (see picture below) 1 -.2m/s/s This was obtained by using the equation Acc=Velocity/Time, acc=-2.5m/s/s / 10s 2.Initial velocity was -.5m/s 3. Speeding up 4. He is moving Backwards After that we further reviewed the Motion analysis Basketball video lab. We learned that the ball slows down on its way up, and its velocity becomes zero at the top. When it moves in a negative direction it gains speed. Lastly, we finished up the conclusions and graph for the lab.
 * Michael Poland **